Some Basic Concepts Of Chemistry Question 105

Question: On reduction with hydrogen, 3.6 g of an oxide of metal left 3.2 g of metal. If the vapour density of metal is 32, the simplest formula of the oxide would be

Options:

A) $ MO $

B) $ M _2O _3 $

C) $ M _2O $

D) $ M _2O _5 $

Show Answer

Answer:

Correct Answer: C

Solution:

[c] As we know that Equivalent weight $ =\frac{\text{weight of metal}}{\text{weight of oxygen}}\times 8 $

$ =\frac{32}{0.4}\times 8=64 $

Vapour density $ =\frac{mol\text{. wt}}{2} $

Mol. wt $ =2\times V.D=2\times 32=64 $

As we know that $ n=\frac{mol\text{.},wt}{eq\text{. wt}}=\frac{64}{64}=1 $ Suppose, the formula of metal oxide be $ M _2O _{n} $ . Hence the formula of metal oxide $ =M _2O $ .



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