Some Basic Concepts Of Chemistry Question 1
Question: X and Y are two elements which form $ X _2Y _3 $ and $ X _3Y _4 $ . If 0.20 mol of $ X _2Y _3 $ weighs 32.0 g and 0.4 mol of $ X _3Y _4 $ weighs 92.8 g, the atomic weights of $ X $ and $ Y $ Fare respectively
Options:
A) 16.0 and 56.0
B) 8.0 and 28.0
C) 56.0 and 16.0
D) 28.0 and 8.0
Show Answer
Answer:
Correct Answer: C
Solution:
Let atomic wt. of $ X=xgmo{l^{-1}} $ Atomic wt. of $ Y=ygmo{l^{-1}} $ $ \frac{32}{2x+3y}=0.2; $
$ \frac{92.8}{3x+4y}=0.4 $ Hence X=56 and Y=16.
