Solutions Question 93

Question: The molal boiling point constant for water is $ {{0.513}^{o}}C,kg,mo{l^{-1}} $ . When 0.1 mole of sugar is dissolved in $ 200ml $ of water, the solution boils under a pressure of one atmosphere at [AIIMS 1991]

Options:

A) $ {{100.513}^{o}}C $

B) $ {{100.0513}^{o}}C $

C) $ {{100.256}^{o}}C $

D) $ {{101.025}^{o}}C $

Show Answer

Answer:

Correct Answer: C

Solution:

$ \Delta T_{b}=K_{b}\times m=0.513\times ( \frac{0.1}{200}\times 1000 ) $

$ =0.2565{{,}^{o}}C $ , $ T_{b}=100.256^{o}C $



NCERT Chapter Video Solution

Dual Pane