Solutions Question 90
Question: Elevation in boiling point was $ {{0.52}^{o}}C $ when $ 6,gm $ of a compound $ X $ was dissolved in $ 100,gm $ of water. Molecular weight of $ X $ is $ (K_{b} $ for water is 0.52 per 1000 gm of water) [CPMT 1989]
Options:
A) 120
B) 60
C) 180
D) 600
Show Answer
Answer:
Correct Answer: B
Solution:
$ \Delta T_{b}=\frac{100\times K_{b}\times w}{m\times W} $ \ $ 0.52=\frac{100\times 5.2\times 6}{m\times 100} $
$ m=\frac{100\times 5.2\times 6}{0.52\times 100}=60 $ .
