Solutions Question 82

Question: Calculate the molal depression constant of a solvent which has freezing point 16.6oC and latent heat of fusion 180.75,Jg1 . [Orissa JEE 2005]

Options:

A) 2.68

B) 3.86

C) 4.68

D) 2.86t6

Show Answer

Answer:

Correct Answer: B

Solution:

Kf=RTf21000×Lf , R=8.314JK1mol1

,Tf=273+16.6=289.6K ; Lf=180.75,Jg1

Kf=8.314×289.6×289.61000×180.75=3.86



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