Solutions Question 61
Question: Molal depression constant for water is $ {{1.86}^{o}}C $ . The freezing point of a 0.05 molal solution of a non-electrolyte in water is [MNR 1990; MP PET 1997]
Options:
A) $ -{{1.86}^{o}}C $
B) $ -{{0.93}^{o}}C $
C) $ -{{0.093}^{o}}C $
D) $ {{0.93}^{o}}C $
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Answer:
Correct Answer: C
Solution:
$ \Delta T_{f}=K_{f}\times molality=1\text{.86}\times 0\text{.05}=0\text{.093} $ °C Thus freezing point = 0 - 0.093 = $ -{{0.093}^{o}}C $ .