Solutions Question 54

Question: Normal boiling point of water is 373 K (at 760mm). Vapour pressure of water at 298 K is 23 mm. If the enthalpy of evaporation is 40.656 kJ/mole, the boiling point of water at 23 mm pressure will be [CBSE PMT 1995]

Options:

A) 250 K

B) 294 K

C) 51.6 K

D) 12.5 K

Show Answer

Answer:

Correct Answer: B

Solution:

Applying clausius clapeytron equation logP2P1=ΔHV2.303R[T2T1T1×T2]

log76023=406562.303×8.314[373T1373T] This gives T1=294.4K .



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