SATHEE: Solutions Question 46

Solutions Question 46

Question: Vapour pressure of a solution of $5 g$ of non- electrolyte in $100 g$ of water at a particular temperature is $2985, N / m^{2}$ . The vapour pressure of pure water is $3000 N / m^{2}$ . The molecular weight of the solute is [IIT Screening 1993]

Options:

A) 60

B) 120

C) 180

D) 380

Show Answer

Answer:

Correct Answer: C

Solution:

$\frac{P^{o} - P_{s}}{P^{o}} = \frac{\frac{W_{2}}{M_{2}}}{\frac{W_{1}}{M_{1}}}$ = $\frac{3000 - 2985}{3000} = \frac{\frac{5}{M_{2}}}{\frac{100}{18}} or M_{2} = 180$

Solutions Question 46

Question: Vapour pressure of a solution of $5 g$ of non- electrolyte in $100 g$ of water at a particular temperature is $2985, N / m^{2}$ . The vapour pressure of pure water is $3000 N / m^{2}$ . The molecular weight of the solute is [IIT Screening 1993]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Solutions Question 46

Question: Vapour pressure of a solution of 5g of non- electrolyte in 100g of water at a particular temperature is 2985,N/m2 . The vapour pressure of pure water is 3000N/m2 . The molecular weight of the solute is [IIT Screening 1993]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Vapour pressure of a solution of $5 g$ of non- electrolyte in $100 g$ of water at a particular temperature is $2985, N / m^{2}$ . The vapour pressure of pure water is $3000 N / m^{2}$ . The molecular weight of the solute is [IIT Screening 1993]