Solutions Question 40

Question: For 0.1 M solution, the colligative property will follow the order [AMU 2000]

Options:

A) $ NaCl>Na_2SO_4>Na_3PO_4 $

B) $ NaCl<Na_2SO_4<Na_3PO_4 $

C) $ NaCl>Na_2SO_4\approx Na_3PO_4 $

D) $ NaCl<Na_2SO_4=Na_3PO_4 $

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Answer:

Correct Answer: B

Solution:

Colligative property in decreasing order $ Na_3PO_4>Na_2SO_4>NaCl $

$ Na_3PO_4\to 3N{a^{+}}+PO_4^{3-}=4 $

$ Na_2SO_4\to 2N{a^{+}}+SO_4^{2-}=3 $

$ NaCl\to N{a^{+}}+C{l^{-}}=2 $



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