SATHEE: Solutions Question 398

Solutions Question 398

Question: The vapour pressure of two pure liquids A and B which form an ideal solution are 1000 and 1600 torr respectively at 400 K. A liquid solution of A and B for which the mole fraction of A is 0.60 is contained in a cylinder by a piston on which the pressure can be varied. The solution use slowly vapourised at 400 K by decreasing the applied pressure. What is the composition of last droplet of liquid remaining in equilibrium with vapour-

Options:

A) $X_{A} = 0.30, X_{B} = 0.70$

B) $X_{A} = 0.40, X_{B} = 0.60$

C) $X_{A} = 0.70, X_{B} = 0.30$

D) $X_{A} = 0.50, X_{B} = 0.50$

Show Answer

Answer:

Correct Answer: C

Solution:

$p_{A}^{0} = 1000$ torr $p_{B}^{0} = 1600$ $X_{A} = 0.6$

$Y_{A} = 0.6$ (from graph) $Y_{A} = \frac{p_{A}^{0} X_{A}}{p_{A}^{0} X_{A} + p_{B}^{0} (1 - X_{A})}$ $0.6 = \frac{1000 X_{A}}{1000 X_{A} + 1600 (1 - X_{A})}$ $X X_{A} = 0.70 X X_{B} = 1 - X_{A} = 0.30$

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Solutions Question 398

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