Solutions Question 393

Question: Find the molality of $ H_2SO_4 $ solution whose specific gravity is $ 1.98,g,m{l^{-}} $ and 95% of volume is $ H_2SO_4 $ .

Options:

A) 7.412

B) 8.412

C) 9.412

D) 10.412

Show Answer

Answer:

Correct Answer: C

Solution:

$ H_2SO_4 $ is 95% by volume, so wt. of $ H_2SO_4=95,g $ Vol. of solution = 100 ml

$ \therefore $ Moles of $ H_2SO_4=\frac{95}{98}. $

And weight of solution $ =100\times 1.98=198g $

Weight of water $ =198-95=103g $

Molality $ =\frac{95\times 1000}{98\times 103}=9.412 $

Hence, molality of $ H_2SO_4 $ solution is 9.412.



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