Solutions Question 380

Question: The vapour pressure of pure liquid solvent A is atm. When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm. What is the mole fraction of component B in the solution'

Options:

A) 0.75

B) 0.25

C) 0.40

D) 0.60

Show Answer

Answer:

Correct Answer: B

Solution:

$ p=X_{A}p^{o}\cdot X_{A}=\frac{p}{p^{o}}=\frac{0.60,atm}{0.80,atm}=0.75 $ $ X_{B}=1-0.75=0.25 $



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