SATHEE: Solutions Question 374

Solutions Question 374

Question: At $17^{\circ} C$ , the osmotic pressure of sugar solution is 580 torr. The solution is diluted and the temperature is raised to $57^{\circ} C,$ when the osmotic pressure is found to be 165 torr. The extent of dilution is:

Options:

A) 2 times

B) 3 times

C) 4 times

D) 5 times

Show Answer

Answer:

Correct Answer: C

Solution:

$π_{1} = \frac{n R T_{1}}{V_{1}}, π_{2} = \frac{n R T_{2}}{V_{2}}$ Hence $\frac{π_{1}}{π_{2}} = \frac{580}{165} = \frac{V_{2} T_{1}}{V_{1} T_{2}} = \frac{V_{2} \times 290}{V_{1} \times 330}$
$\Rightarrow \frac{V_{2}}{V_{1}} = 4$

Solutions Question 374

Question: At $17^{\circ} C$ , the osmotic pressure of sugar solution is 580 torr. The solution is diluted and the temperature is raised to $57^{\circ} C,$ when the osmotic pressure is found to be 165 torr. The extent of dilution is:

Options:

Answer:

Solution:

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Solutions Question 374

Question: At 17∘C , the osmotic pressure of sugar solution is 580 torr. The solution is diluted and the temperature is raised to 57∘C, when the osmotic pressure is found to be 165 torr. The extent of dilution is:

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: At $17^{\circ} C$ , the osmotic pressure of sugar solution is 580 torr. The solution is diluted and the temperature is raised to $57^{\circ} C,$ when the osmotic pressure is found to be 165 torr. The extent of dilution is: