Solutions Question 372

Question: Benzene freezes at 5.50C . If the freezing point of 2.48 g of phosphorous in 100 g benzene is 4.48C , the atomicity of phosphorus in benzene is ( Kf (benzene) =5.12,K,kgmol1 ):

Options:

A) 1

B) 3

C) 4

D) 8

Show Answer

Answer:

Correct Answer: C

Solution:

Molecular mass of phosphorous =1000×Kf×WsoluteΔTf×Wbenzene

=1000×5.12×2.481.02×100=124.5=(P)x Or , x=124.531=4



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