Solutions Question 371

Question: On mixing 3 g of non - volatile solute in 200 mL of water, its boiling point (100∘) becomes 100.52∘C. If Kb for water is 0.6 K/m then molecular wt. of solute is:

Options:

A) 10.5gmol−1

B) 12.6gmol−1

C) 15.7,gmol−1

D) 17.3,gmol−1

Show Answer

Answer:

Correct Answer: D

Solution:

ΔTb=KbwM×1000W

0.52=0.6×3m×1000200(W=200×1)

m=1.8×50.52=17.3g,mol−1

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