Solutions Question 355

Question: Freezing point of an aqueous solution is 0.186C. If the values of Kb and Kf of water are respectively 0.52Kkgmol1 and 1.86Kkgmol1 , then the elevation of boiling point of the solution in K is

Options:

A) 0.52

B) 1.04

C) 1.34

D) 0.052

Show Answer

Answer:

Correct Answer: D

Solution:

ΔTf=i.Kf.m;ΔTb=i.Kb.m

ΔTfΔTb=KfKb

ΔTf=0(0.186C)=0.186C

0.186ΔTb=1.860.52ΔTb=0.52×0.1861.86=0.052



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