SATHEE: Solutions Question 353

Solutions Question 353

Question: The difference between the boiling point and freezing point of an aqueous solution containing sucrose (molecular $w t = 342 g m o l e^{- 1}$ ) in 100 g of water is $105^{\circ} C$ . If $K_{f}$ and $K_{b}$ of water are 1.86 and $0.51 K k g m o l^{- 1}$ respectively, the weight of sucrose in the solution is about

Options:

A) 34.2 g

B) 342 g

C) 7.2 g

D) 72 g

Show Answer

Answer:

Correct Answer: D

Solution:

$(100 + Δ T_{b}) - (0 - Δ T_{f}) = 105$

$Δ T_{b} + Δ T_{f} = 5$

$m (K_{b} + K_{f}) = 5$

$m = \frac{5}{2.37}$ i.e., $\frac{5}{2.37}$ moles in 1000 g water (or) $\frac{5}{2.37 \times 10}$ moles in 100 g water
$∴$ Wt. of sucrose $= \frac{5}{2.37 \times 10} \times 342 = 72 g$

Solutions Question 353

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Solutions Question 353

Question: The difference between the boiling point and freezing point of an aqueous solution containing sucrose (molecular wt=342gmole−1 ) in 100 g of water is 105∘C . If Kf and Kb of water are 1.86 and 0.51Kkgmol−1 respectively, the weight of sucrose in the solution is about

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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