SATHEE: Solutions Question 344

Solutions Question 344

Question: The observed osmotic pressure for a 0.10 M solution of $F e {(N H_{4})}_{2} {(S O_{4})}_{2}, a t, 25^{\circ} C$ is 10.8 atm. The experimental (observed) value of van’t Hoff factor will be: $(R = 0.082 L a t m k^{- 1} m o l^{- 1})$

Options:

A) 4.42

B) 4.00

C) 3.42

D) 5.42

Show Answer

Answer:

Correct Answer: A

Solution:

Given $π_{o b} = 10.8 a t m$

$π_{n o r} = C R T = 0.10 \times 0.0821 \times 298 = 2.446$ now experimental value of (i) $= \frac{O b s e r v e d o s m o t i c p r e s s u r e}{N o r m a l o s m o t i c p r e s s u r e}$

$= \frac{10.8}{2.446} = 4.42$

Solutions Question 344

Question: The observed osmotic pressure for a 0.10 M solution of $F e {(N H_{4})}_{2} {(S O_{4})}_{2}, a t, 25^{\circ} C$ is 10.8 atm. The experimental (observed) value of van’t Hoff factor will be: $(R = 0.082 L a t m k^{- 1} m o l^{- 1})$

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Solutions Question 344

Question: The observed osmotic pressure for a 0.10 M solution of Fe(NH4)2(SO4)2,at,25∘C is 10.8 atm. The experimental (observed) value of van’t Hoff factor will be: (R=0.082Latmk−1mol−1)

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: The observed osmotic pressure for a 0.10 M solution of $F e {(N H_{4})}_{2} {(S O_{4})}_{2}, a t, 25^{\circ} C$ is 10.8 atm. The experimental (observed) value of van’t Hoff factor will be: $(R = 0.082 L a t m k^{- 1} m o l^{- 1})$