Solutions Question 334

Question: The temperature at which 10% aqueous solution (w/v) of glucose will exhibit the osmotic pressure of 14 bar is -

Options:

A) $ 307.3{}^\circ C $

B) 307.3 K

C) 34 K

D) $ -34{}^\circ C $

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Answer:

Correct Answer: B

Solution:

$ \pi =\frac{nRT}{V} $ or $ T=\frac{\pi V}{nR} $ 10% (w/v) aqueous solution of glucose means 10 g glucose is present in 100 mL of $ H_2O $

$ =\frac{14\times 100\times {10^{-3}}\times 180}{0.082\times 10}=307.3K $



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