SATHEE: Solutions Question 333

Solutions Question 333

Question: The elevation in boiling point of a solution of 13.44 g of $C u C l_{2}$ in 1 kg of water using the following information will be (Molecular weight of $C u C l_{2} = 134.4 g$ and $K_{b} = 0.52, K k g, m o l^{- 1}$ )

Options:

A) 0.16

B) 0.05

C) 0.1

D) 0.2

Show Answer

Answer:

Correct Answer: A

Solution:

(i) $i = \frac{N o . o f p a r t i c l e s a f t e r i o n i s a t i o n}{N o . o f p a r t i c l e s b e f o r e i o n i s a t i o n}$ (ii) $Δ T_{b} = i \times K_{b} \times m$

$i = \frac{1 + 2 α}{1}, = 1 + 2 α$ Assuming 100% ionization So, $i = 1 + 2 = 3$

$Δ T_{b} = 3 \times 0.52 \times 0.1 = 0.156 \approx 0.16$

$(m = \frac{13.44}{134.4} = 0.1)$

Privacy Policy

Powered by Prutor@IITK

sathee@iitk.ac.in

Media coverage of SATHEE

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Solutions Question 333

Question: The elevation in boiling point of a solution of 13.44 g of CuCl2 in 1 kg of water using the following information will be (Molecular weight of CuCl2=134.4g and Kb=0.52,Kkg,mol−1 )

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

Question: The elevation in boiling point of a solution of 13.44 g of $C u C l_{2}$ in 1 kg of water using the following information will be (Molecular weight of $C u C l_{2} = 134.4 g$ and $K_{b} = 0.52, K k g, m o l^{- 1}$ )