Solutions Question 315

Options:

A) $ M_{A}=M_{B} $

B) $ 2M_{A}=M_{B} $

C) $ M_{A}=2M_{B} $

D) $ M_{A}=4M_{B} $

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Answer:

Correct Answer: C

Solution:

For dilute solution, $ \frac{\Delta P}{P{}^\circ }\Rightarrow \frac{n_{solute}}{n_{solvent}} $ For solution in A, $ \frac{\Delta P_{A}}{P_A^{{}^\circ }}=\frac{W/M}{W_{A}/M_{A}}=\frac{W}{M}\times \frac{M_{A}}{W_{A}} $ …(i) For solution in B, $ \frac{\Delta P_{B}}{P_A^{{}^\circ }}=\frac{W}{M}\times \frac{M_{B}}{W_{B}} $ ….(ii) From (i) and (ii),

$ \frac{\Delta P _{A}/{P^{\circ} } _{A}}{\Delta P _{B}/{P^{\circ} } _{B}}=$

$2=\frac{M_{A}W_{B}}{M_{B}W_{A}}=\frac{M_{A}}{W_{B}}(W_{A}=W_{B}) $

$ M_{A}=2M_{B} $



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