SATHEE: Solutions Question 312

Solutions Question 312

Question: Vapour pressure (in torr) of an ideal solution of two liquids A and B is given by: $P = 52 X_{A} + 114$ where $X_{A}$ is the mole fraction of A in the mixture. The vapour pressure (in torr) of equimolar mixture of the two liquids will be:

Options:

A) 166

B) 83

C) 140

D) 280

Show Answer

Answer:

Correct Answer: C

Solution:

Total V.P., $P = P_{A}^{0} X_{A} + P_{B}^{0} X_{B} = P_{A}^{0} X_{A} + P_{B}^{0} (1 - X_{A})$

$= (P_{A}^{0} - P_{B}^{0}) X_{A} + P_{B}^{0}$ Thus, $P_{B}^{\circ} = 114, t o r r; P_{A}^{0} - P_{B}^{0} = 52$ or $P_{A}^{0} = 166 t o r r$ Hence $P = 166 \times \frac{1}{2} + 114 \times \frac{1}{2} = 140 t o r r$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Solutions Question 312

Question: Vapour pressure (in torr) of an ideal solution of two liquids A and B is given by: P=52XA+114 where XA is the mole fraction of A in the mixture. The vapour pressure (in torr) of equimolar mixture of the two liquids will be:

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

Question: Vapour pressure (in torr) of an ideal solution of two liquids A and B is given by: $P = 52 X_{A} + 114$ where $X_{A}$ is the mole fraction of A in the mixture. The vapour pressure (in torr) of equimolar mixture of the two liquids will be: