SATHEE: Solutions Question 310

Solutions Question 310

Question: Vapour pressure of chloroform $(C H C l_{3})$ and dichloromethane $(C H_{2} C l_{2})$ at $25^{\circ}$ C are 200 mm Hg and 41.5 mm Hg respectively. Vapour pressure of the solution obtained by mixing 25.5 g of $C H C l_{3}$ and 40 g of $C H_{2} C l_{2}$ at the same temperature will be: (Molecular mass of $C H C l_{3} = 119.5 u$ and molecular mass of $C H_{2} C l_{2} = 85 u$ ).

Options:

A) 90.92 mm Hg

B) 115.0 mm Hg

C) 147.9 mm Hg

D) 285.5 mm Hg

Show Answer

Answer:

Correct Answer: A

Solution:

$^{n} C H C l_{3} = \frac{25.5}{119.5} = 0.213$

$^{n} C H_{2} C l_{2} = \frac{40}{85} = 0.47$

$P_{T} = P_{A}^{0} X_{A} + P_{B}^{0} X_{B}$

$= 200 \times \frac{0.213}{0.683} + 41.5 \times \frac{0.47}{0.683}$

$= 62.37 + 28.55 = 90.92$

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Solutions Question 310

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