Solutions Question 302
Question: Two solutions of a substance (non-electrolyte) are mixed in the following manner. 480 mL of 1.5 M first solution +520 mL of 1.2 M second solution. What is the molarity of the final mixture-
Options:
A) 2.70 M
B) 1.344 M
C) 1.50 M
D) 1.20 M
Show Answer
Answer:
Correct Answer: B
Solution:
From the molarity equation. $ M_1V_1+M_2V_2=MV $
$ M=\frac{M_1V_1+M_2V_2}{V} $ where $ V=V_1+V_2 $
$ M=\frac{480\times 1.5+520\times 1.2}{480+520}=1.344M $
