Solutions Question 235
Question: How many moles of water are present in 180 $ g $ of water [JIPMER 1991; DPMT 1982; Manipal MEE 1995]
Options:
A) 1 mole
B) 18 mole
C) 10 mole
D) 100 mole
Show Answer
Answer:
Correct Answer: C
Solution:
Moles of water $ =\frac{180}{18}=10,mole\text{.} $