Solutions Question 235

Question: How many moles of water are present in 180 $ g $ of water [JIPMER 1991; DPMT 1982; Manipal MEE 1995]

Options:

A) 1 mole

B) 18 mole

C) 10 mole

D) 100 mole

Show Answer

Answer:

Correct Answer: C

Solution:

Moles of water $ =\frac{180}{18}=10,mole\text{.} $



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