Solutions Question 228

Question: The weight of sodium carbonate required to prepare 500 ml of a semi­- normal solution is [JIPMER 1999]

Options:

A) 13.25 g

B) 26.5 g

C) 53 g

D) 6.125 g

Show Answer

Answer:

Correct Answer: A

Solution:

N=w×1000eq.,wt.×volumeinml.

eq.,wt.=1062=53

w=0.5×53×5001000=13.25 .



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