SATHEE: Solutions Question 224

Solutions Question 224

Question: If 0.50 mol of $C a C l_{2}$ is mixed with 0.20 mol of $N a_{3} P O_{4}$ , the maximum number of moles of $C a_{3} {(P O_{4})}_{2}$ which can be formed, is [Pb. PMT 1998]

Options:

A) 0.70

B) 0.50

C) 0.20

D) 0.10

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Answer:

Correct Answer: D

Solution:

$3, C a C l_{2} + 2, N a_{3} P O_{4} \to C a_{3} {(P O_{4})}_{2} + 6 N a C l$
$∴$ Mole of $N a_{3} P O_{4} = 3$ mole of $C a C l_{2} = 1$ mole $C a_{3} {(P O_{4})}_{2}$
$∴$ 0.2 mole of $N a_{3} P O_{4} = 0.3$ mole of $C a C l_{2}$ = 0.1 mole of $C a_{3} {(P O_{4})}_{2}$ .

Solutions Question 224

Question: If 0.50 mol of $C a C l_{2}$ is mixed with 0.20 mol of $N a_{3} P O_{4}$ , the maximum number of moles of $C a_{3} {(P O_{4})}_{2}$ which can be formed, is [Pb. PMT 1998]

Options:

Answer:

Solution:

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Solutions Question 224

Question: If 0.50 mol of CaCl2 is mixed with 0.20 mol of Na3PO4 , the maximum number of moles of Ca3(PO4)2 which can be formed, is [Pb. PMT 1998]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: If 0.50 mol of $C a C l_{2}$ is mixed with 0.20 mol of $N a_{3} P O_{4}$ , the maximum number of moles of $C a_{3} {(P O_{4})}_{2}$ which can be formed, is [Pb. PMT 1998]