SATHEE: Solutions Question 216

Solutions Question 216

Question: To neutralise completely 20 mL of 0.1 M aqueous solution of phosphorous acid $(H_{3} P O_{3}),$ the volume of 0.1 M aqueous KOH solution required is [AIEEE 2004]

Options:

A) 40 mL

B) 20 mL

C) 10 mL

D) 60 mL

Show Answer

Answer:

Correct Answer: A

Solution:

$H_{3} P O_{3}$ is a dibasic acid $N_{1} V_{1}$ (acid) $= N_{2} V_{2}$ (base) $0.1 \times 2 \times 20 = 0.1 \times 1 \times V_{2}$
$∴$ $V_{2} = \frac{0.1 \times 2 \times 20}{0.1 \times 1} = 40, m l$

Solutions Question 216

Question: To neutralise completely 20 mL of 0.1 M aqueous solution of phosphorous acid $(H_{3} P O_{3}),$ the volume of 0.1 M aqueous KOH solution required is [AIEEE 2004]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Solutions Question 216

Question: To neutralise completely 20 mL of 0.1 M aqueous solution of phosphorous acid (H3PO3), the volume of 0.1 M aqueous KOH solution required is [AIEEE 2004]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: To neutralise completely 20 mL of 0.1 M aqueous solution of phosphorous acid $(H_{3} P O_{3}),$ the volume of 0.1 M aqueous KOH solution required is [AIEEE 2004]