Solutions Question 203

Question: In a solution of $ 7.8,gm $ benzene $ C_6H_6 $ and $ 46.0,gm $ toluene $ (C_6H_5CH_3) $ , the mole fraction of benzene in this solution is [BHU 1981, 87]

Options:

A) $ 1/6 $

B) $ 1/5 $

C) $ 1/2 $

D) $ 1/3 $

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Answer:

Correct Answer: A

Solution:

Mole fraction at $ C_6H_6=\frac{\frac{7.8}{78}}{\frac{7.8}{78}+\frac{46}{92}}=\frac{1}{6} $ .



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