Solutions Question 200

Question: $ 6.02\times 10^{20} $ molecules of urea are present in 100 ml of its solution. The concentration of urea solution is [AIEEE 2004]

Options:

A) 0.02 M

B) 0.01 M

C) 0.001 M

D) 0.1 M (Avogadro constant, $ N_{A}=6.02\times 10^{23}mo{l^{-1}}) $

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Answer:

Correct Answer: B

Solution:

Mole of urea $ =\frac{6.02\times 10^{20}}{6.02\times 10^{23}}={10^{-3}} $ moles Conc. of solution (in molarity)



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