Solutions Question 156

Question: The amount of K2Cr2O7 (eq. wt. 49.04) required to prepare 100 ml of its 0.05 N solution is [JIPMER 2002]

Options:

A) 2.9424 g

B) 0.4904 g

C) 1.4712 g

D) 0.2452 g

Show Answer

Answer:

Correct Answer: D

Solution:

W=N×eq.wt.×V(ml)1000=0.05×49.04×1001000

=0.2452.



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