Solutions Question 146

Question: A mixture has 18g water and 414g ethanol. The mole fraction of water in mixture is (assume ideal behaviour of the mixture) [MP PMT 2000]

Options:

A) 0.1

B) 0.4

C) 0.7

D) 0.9

Show Answer

Answer:

Correct Answer: A

Solution:

Molecular weight of $ C_2H_5OH=24+5+16+1=46 $

Molecular mass of $ H_2O=18 $

414g of $ C_2H_5OH $ has $ \frac{414}{46}=9 $ mole

18g of $ H_2O $ has $ =\frac{18}{18}=1 $ mole

Mole fraction of water $ =\frac{n_1}{n_1+n_2}=\frac{1}{1+9} $

$ =\frac{1}{10}=0.1 $



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