Solutions Question 144

Question: How much of NaOH is required to neutralise 1500 $ cm^{3} $ of 0.1 N HCl (At. wt. of Na =23) [KCET 2001]

Options:

A) 4 g

B) 6 g

C) 40 g

D) 60 g

Show Answer

Answer:

Correct Answer: B

Solution:

1500 $ cm^{3} $ of 0.1 N HCl have number of gm equivalence $ =\frac{N_1\times V_1}{1000}=\frac{1500\times 0.1}{1000}=0.15 $
$ \therefore 0.15,gm. $ equivalent of NaOH $ =0.15\times 40=6,gm. $



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