SATHEE: Solutions Question 143

Solutions Question 143

Question: $20, m l$ of $H C l$ solution requires $19.85, m l$ of $0.01, M, N a O H$ solution for complete neutralization. The molarity of $H C l$ solution is [MP PMT 1999]

Options:

A) 0.0099

B) 0.099

C) 0.99

D) 9.9

Show Answer

Answer:

Correct Answer: A

Solution:

$M_{1} V_{1} = M_{2} V_{2}$

$0.01 \times 19.85 = M_{2} \times 20$

$M_{2} = 0.009925$ ; $M = 0.0099$ .

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Solutions Question 143

Question: 20,ml of HCl solution requires 19.85,ml of 0.01,M,NaOH solution for complete neutralization. The molarity of HCl solution is [MP PMT 1999]

Options:

Answer:

Solution:

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Question: $20, m l$ of $H C l$ solution requires $19.85, m l$ of $0.01, M, N a O H$ solution for complete neutralization. The molarity of $H C l$ solution is [MP PMT 1999]