Solutions Question 135

Question: The amount of anhydrous $ Na_2CO_3 $ present in 250 ml of 0.25 M solution is [DPMT 2001]

Options:

A) 6.225 g

B) 66.25 g

C) 6.0 g

D) 6.625 g

Show Answer

Answer:

Correct Answer: D

Solution:

$ M=\frac{w}{m\times V(l)} $ ; $ 0.25=\frac{w}{106\times 0.25} $ ; $ w=6.625 $ gm



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