SATHEE: Solutions Question 132

Solutions Question 132

Question: If two substances $A$ and $B$ have $P_{A}^{0} :, P_{B}^{0} = 1, :, 2$ and have mole fraction in solution 1 : 2 then mole fraction of $A$ in vapours [DPMT 2005]

Options:

A) 0.33

B) 0.25

C) 0.52

D) 0.2

Show Answer

Answer:

Correct Answer: D

Solution:

Relationship between mole fraction of a component in the vapour phase and total vapour pressure of an ideal solution. $y_{A} = \frac{P_{A}}{P_{t o t a l}} = \frac{x_{A} . P_{A}^{0}}{x_{A} . P_{A}^{0} + x_{B} . P_{B}^{0}}$

$= \frac{1 \times 1}{1 \times 1 + 2 \times 2} = \frac{1}{1 + 4} = \frac{1}{5} = 0.2$

Solutions Question 132

Question: If two substances $A$ and $B$ have $P_{A}^{0} :, P_{B}^{0} = 1, :, 2$ and have mole fraction in solution 1 : 2 then mole fraction of $A$ in vapours [DPMT 2005]

Options:

Answer:

Solution:

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Solutions Question 132

Question: If two substances A and B have PA0:,PB0=1,:,2 and have mole fraction in solution 1 : 2 then mole fraction of A in vapours [DPMT 2005]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: If two substances $A$ and $B$ have $P_{A}^{0} :, P_{B}^{0} = 1, :, 2$ and have mole fraction in solution 1 : 2 then mole fraction of $A$ in vapours [DPMT 2005]