SATHEE: Solutions Question 123

Solutions Question 123

Question: An aqueous solution of glucose was prepared by dissolving 18 g of glucose in 90 g of water. The relative lowering in vapour pressure is [KCET 2002]

Options:

A) 0.02

B) 1

C) 20

D) 180

Show Answer

Answer:

Correct Answer: A

Solution:

$\frac{P^{0} - P s}{P^{0}} = \frac{18 \times 18}{180 \times 90} = 0.02$ .

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Solutions Question 123

Question: An aqueous solution of glucose was prepared by dissolving 18 g of glucose in 90 g of water. The relative lowering in vapour pressure is [KCET 2002]

Options:

Answer:

Solution:

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