Redox Reactions And Electrochemistry Ques 78
Question: Given $ l/a=0.5c{m^{-1}},,R=50ohm,,N=1.0 $ . The equivalent conductance of the electrolytic cell is [Orissa JEE 2005]
Options:
A) $ 10,oh{m^{-1}}cm^{2}gm,e{q^{-1}} $
B) $ 20,oh{m^{-1}}cm^{2}gm,e{q^{-1}} $
C) $ 300,oh{m^{-1}}cm^{2}gme{q^{-1}} $
D) $ 100oh{m^{-1}}cm^{2},gme{q^{-1}} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ l/a=0.5,c{m^{-1}},,R=50,ohm $ $ p=\frac{Ra}{l}=\frac{50}{0.5}=100 $
$ \Lambda =k\times \frac{1000}{N}=\frac{1}{p}\times \frac{1000}{N}=\frac{1}{100}\times \frac{1000}{1} $
$ 10,oh{m^{-1}}cm^{2},gm,e{q^{-1}} $
