SATHEE: Redox Reactions And Electrochemistry Ques 78

Redox Reactions And Electrochemistry Ques 78

Question: Given $l / a = 0.5 c m^{- 1},, R = 50 o h m,, N = 1.0$ . The equivalent conductance of the electrolytic cell is [Orissa JEE 2005]

Options:

A) $10, o h m^{- 1} c m^{2} g m, e q^{- 1}$

B) $20, o h m^{- 1} c m^{2} g m, e q^{- 1}$

C) $300, o h m^{- 1} c m^{2} g m e q^{- 1}$

D) $100 o h m^{- 1} c m^{2}, g m e q^{- 1}$

Show Answer

Answer:

Correct Answer: A

Solution:

$l / a = 0.5, c m^{- 1},, R = 50, o h m$ $p = \frac{R a}{l} = \frac{50}{0.5} = 100$

$Λ = k \times \frac{1000}{N} = \frac{1}{p} \times \frac{1000}{N} = \frac{1}{100} \times \frac{1000}{1}$

$10, o h m^{- 1} c m^{2}, g m, e q^{- 1}$

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Redox Reactions And Electrochemistry Ques 78

Question: Given l/a=0.5cm−1,,R=50ohm,,N=1.0 . The equivalent conductance of the electrolytic cell is [Orissa JEE 2005]

Options:

Answer:

Solution:

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Question: Given $l / a = 0.5 c m^{- 1},, R = 50 o h m,, N = 1.0$ . The equivalent conductance of the electrolytic cell is [Orissa JEE 2005]