SATHEE: Redox Reactions And Electrochemistry Ques 762

Redox Reactions And Electrochemistry Ques 762

Question: $6 \times 10^{- 3}$ mole $K_{2} C r_{2} O_{7}$ reacts completely with $9 \times 10^{- 3}$ mole of $x^{n +}$ to give $X O_{3}^{-}$ and $C r^{3 +}$ . Value of n will be

Options:

A) 1

B) 3

C) 2

D) 4

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $K_{2} C r_{2} O_{7} + X^{n +} \to_{}^{} X^{5 +} O_{3}^{-} + C r^{3 +}$ $6 \times 10^{- 3} \times 6 = (5 - n) \times 9 \times 10^{- 3}$ Implies $n = 1$ In $K_{2} C r_{2} O_{7}$ oxidation state of $C r = 6$ X have change in oxidation number $= (5 - n)$ .

Redox Reactions And Electrochemistry Ques 762

Question: $6 \times 10^{- 3}$ mole $K_{2} C r_{2} O_{7}$ reacts completely with $9 \times 10^{- 3}$ mole of $x^{n +}$ to give $X O_{3}^{-}$ and $C r^{3 +}$ . Value of n will be

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Redox Reactions And Electrochemistry Ques 762

Question: 6×10−3 mole K2Cr2O7 reacts completely with 9×10−3 mole of xn+ to give XO3− and Cr3+ . Value of n will be

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

Question: $6 \times 10^{- 3}$ mole $K_{2} C r_{2} O_{7}$ reacts completely with $9 \times 10^{- 3}$ mole of $x^{n +}$ to give $X O_{3}^{-}$ and $C r^{3 +}$ . Value of n will be