Redox Reactions And Electrochemistry Ques 746
Question: Oxidation number of cobalt in $ [Co{{(NH_3)}_6}]Cl_2Br $ is -
Options:
A) + 6
B) zero
C) + 3
D) + 2
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Let the O.N. of Co be x O.N. of $ NH_3 $ is zero O.N. of Cl is - 1 O.N. of Br is - 1
$ \therefore $ $ ON( Co )+6ON( NH_3 )+2ON( Cl ) $ $ +ON( Br )=0 $
$ \Rightarrow $ $ x+6( 0 )-1\times 2-1=0 $
$ \therefore $ $ x=+3 $ So, the oxidation number of cobalt in the given complex compound is +3.
