SATHEE: Redox Reactions And Electrochemistry Ques 710

Redox Reactions And Electrochemistry Ques 710

Question: Emf of the cell

$N i | N i^{2 +} (0.1, M) | | A u^{3 +}, (1.0, M) |, A u$ will be $(E_{N i / N i^{2 +}}^{^{\circ}} = 0.25,, E_{A u / A u^{3 +}}^{^{\circ}} = 1.5, V)$

Options:

A) 1.75 V

B) $+$ 1.7795 V

C) $+$ 0.7795 V

D) $-$ 1.7795 V

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Cell reaction: $3 N i + 2 A u^{+ 3} \overset{}{\to} 3 N i^{+ 2} + 2 A u$

$E_{c e l l} = E_{c e l l}^{^{\circ}} - \frac{0.0591}{6} \log, \frac{{[N i^{+ 2}]}^{3}}{{[A u^{+ 3}]}^{2}}$

$= (0.25 + 1.5) - \frac{0.0591}{6} \log \frac{{(0.1)}^{3}}{{(1)}^{2}}$

$= 1.75 - \frac{0.0591}{2} \log, (.1), =, 1.75 + 0.295 = + 1.7795, V$

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Redox Reactions And Electrochemistry Ques 710

Question: Emf of the cell

Options:

Answer:

Solution:

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