Redox Reactions And Electrochemistry Ques 675

Question: Which of the following statements is not correct-

Options:

A) The oxidation number of S in $ {{(NH_4)}_2}S_2O_8 $ is +6.

B) The oxidation number of Os in $ OsO_4 $ is +8.

C) The oxidation number of S in $ H_2SO_5 $ is +8.

D) The oxidation number of O in $ KO_2 $ is -1/2.

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Answer:

Correct Answer: C

Solution:

[c] [a] $ {{( N{{\overset{+1}{\mathop{H}},}_4} )}_2}S_2O_8^{2-} $
$ \therefore $ Oxidation state of S=+6 (Since $ S_2O_8^{2-} $ has one peroxide bond) [b] Oxidation state of $ Os=+8 $ [c] Oxidation state of S in $ H_2SO_5=+6 $ (Since it has one peroxide bond) [d] $ {{K}^{1+}}O_2^{1-} $ , oxidation state of $ O=-1/2 $



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