Redox Reactions And Electrochemistry Ques 669

Question: The oxidation number of phosphorus in $ Ba{{(H_2PO_2)}_2} $ is

Options:

A) +3

B) +2

C) +1

D) - 1

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $ B{{a}^{2+}}(H_2PO_2)_2^{-1\times 2}:H_2PO_2^{-}:2+x-4=-1 $
$ \Rightarrow x=+1 $
$ \therefore $ Oxidation state of P = + 1



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