SATHEE: Redox Reactions And Electrochemistry Ques 632

Redox Reactions And Electrochemistry Ques 632

Question: Electrode potentials $(E^{\circ})$ are given below:

$C u^{+} / C u = + 0.52 V,$ $F e^{3 +} / F e^{2 +} = + 0.77 V,$ $\frac{1}{2} I_{2} (s) / I^{-} = + 0.54 V,$ $A g^{+} / A g = + 0.88 V$ . Based on the above potentials, strongest oxidizing agent will be:

Options:

A) $C u^{+}$

B) $F e^{3 +}$

C) $A g^{+}$

D) $I_{2}$

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Higher the value of reduction potential stronger will be the oxidising hence based on the given values $A g^{+}$ will be strongest oxidizing agent.

Redox Reactions And Electrochemistry Ques 632

Question: Electrode potentials $(E^{\circ})$ are given below:

Options:

Answer:

Solution:

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Redox Reactions And Electrochemistry Ques 632

Question: Electrode potentials (E∘) are given below:

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Electrode potentials $(E^{\circ})$ are given below: