Redox Reactions And Electrochemistry Ques 632

Question: Electrode potentials $ ( E{}^\circ ) $ are given below:

$ C{u^{+}}/Cu=+0.52V, $ $ F{e^{3+}}/F{e^{2+}}=+0.77V, $ $ \frac{1}{2}I_2(s)/{I^{-}}=+0.54V, $ $ A{g^{+}}/Ag=+0.88V $ . Based on the above potentials, strongest oxidizing agent will be:

Options:

A) $ C{u^{+}} $

B) $ F{e^{3+}} $

C) $ A{g^{+}} $

D) $ I_2 $

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Higher the value of reduction potential stronger will be the oxidising hence based on the given values $ A{g^{+}} $ will be strongest oxidizing agent.



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