SATHEE: Redox Reactions And Electrochemistry Ques 602

Redox Reactions And Electrochemistry Ques 602

Question: The standard electrode potential $(E^{\circ})$ for $O C l^{-} / C l^{-}$ and $C l^{-} / \frac{1}{2} C l_{2}$ respectively are 0.94 V and $- 1.36 V$ . The $E^{\circ}$ value for $O C l^{-} / \frac{1}{2} C l_{2}$ will be

Options:

A) $- 0.42 V$

B) $- 2.20 V$

C) 0.52 V

D) 1.04 V

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $O C l^{-} \overset{}{\to} C l^{-}; E^{\circ} = 0.94 V (I)$ $C l^{-} \overset{}{\to} \frac{1}{2} C l_{2} + e^{-}; E^{\circ} = 1.36 V (I I)$ Add (I)+(II) $O C I^{-} \overset{}{\to} \frac{1}{2} C l_{2}; E^{o} = 0.94 - 1.36$ $= - 0.42 V$

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Redox Reactions And Electrochemistry Ques 602

Question: The standard electrode potential (E∘) for OCl−/Cl− and Cl−/12Cl2 respectively are 0.94 V and −1.36V . The E∘ value for OCl−/12Cl2 will be

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Question: The standard electrode potential $(E^{\circ})$ for $O C l^{-} / C l^{-}$ and $C l^{-} / \frac{1}{2} C l_{2}$ respectively are 0.94 V and $- 1.36 V$ . The $E^{\circ}$ value for $O C l^{-} / \frac{1}{2} C l_{2}$ will be