Redox Reactions And Electrochemistry Ques 602
Question: The standard electrode potential $ ( E{}^\circ ) $ for $ OC{l^{-}}/C{l^{-}} $ and $ C{l^{-}}/\frac{1}{2}Cl_2 $ respectively are 0.94 V and $ -1.36V $ . The $ E{}^\circ $ value for $ OC{l^{-}}/\frac{1}{2}Cl_2 $ will be
Options:
A) $ -0.42V $
B) $ -2.20V $
C) 0.52 V
D) 1.04 V
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ OC{l^{-}}\xrightarrow{{}}C{l^{-}};E{}^\circ =0.94V(I) $ $ C{l^{-}}\xrightarrow{{}}\frac{1}{2}Cl_2+{e^{-}};E{}^\circ =1.36V(II) $ Add (I)+(II) $ OC{I^{-}}\xrightarrow{{}}\frac{1}{2}Cl_2;E^{o}=0.94-1.36 $ $ =-0.42V $
