Redox Reactions And Electrochemistry Ques 589
Question: Electrode potential of the half cell $ Pt( s )|Hg( l )| $ $ Hg_2Cl_2(s)|C{l^{-}}(aq) $ can be increased by:
Options:
A) Increasing $ [ C{l^{-}} ] $
B) Decreasing $ [ C{l^{-}} ] $
C) Increasing $ Hg_2Cl_2(s) $
D) Decreasing $ Hg( l ) $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ E=E{}^\circ -\frac{0.0591}{2}\log \frac{1}{{{[C{l^{-}}]}^{2}}};as,[C{l^{-}}]\downarrow ,E\uparrow $
