Redox Reactions And Electrochemistry Ques 589

Question: Electrode potential of the half cell $ Pt( s )|Hg( l )| $ $ Hg_2Cl_2(s)|C{l^{-}}(aq) $ can be increased by:

Options:

A) Increasing $ [ C{l^{-}} ] $

B) Decreasing $ [ C{l^{-}} ] $

C) Increasing $ Hg_2Cl_2(s) $

D) Decreasing $ Hg( l ) $

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $ E=E{}^\circ -\frac{0.0591}{2}\log \frac{1}{{{[C{l^{-}}]}^{2}}};as,[C{l^{-}}]\downarrow ,E\uparrow $



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