Redox Reactions And Electrochemistry Ques 577

Question: On passing current through two cells, connected in series containing solution of $ AgNO_3 $ and $ CuSO_4 $ , 0.18 g of Ag is deposited. The amount of the Cu deposited is:

Options:

A) 0.529 g

B) 10.623 g

C) 0.0529 g

D) 1.2708 g

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Using Faraday’s second law of electrolysis, $ \frac{Weight,of,Cu,deposoited}{Weight,of,Ag,deposited}=\frac{Equ.,wt.,of,Cu}{Equ.,wt.,of,Ag} $
$ \Rightarrow \frac{w_{Cu}}{0.18}=\frac{63.5}{2}\times \frac{1}{108} $
$ \Rightarrow w_{Cu}=\frac{63.5\times 18}{2\times 108\times 100}=0.0529g. $



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