Redox Reactions And Electrochemistry Ques 549

Question: In the balanced chemical reaction, $ IO_3^{-}+a\ {{I}^{-}}+b\ {{H}^{+}}\to c\ H_2O+d\ I_2 $ a, b, c and d respectively correspond to [AIIMS 2005]

Options:

A) 5, 6, 3, 3

B) 5, 3, 6, 3

C) 3, 5, 3, 6

D) 5, 6, 5, 5

Show Answer

Answer:

Correct Answer: A

Solution:

$IO_3- + aI^- + bH^+ \rightarrow cH_2O + dI_2 $

$Step 1 : I^{-1} \rightarrow I_2 (oxidation) $ $IO_3- \rightarrow I_2 (reduction) $

$Step 2 : 2IO^{3-} + 12H+ \rightarrow I_2 + 6H_2O $

$Step 3 : 2IO3- + 12H+ + 10e \rightarrow I2 + 6H_2O $ $ 2I^- \rightarrow I_2 + 2e $

$Step 4 : 2IO3- + 12H+ + 10e- \rightarrow I2 + 6H_2O $ $[2I^- \rightarrow I_2 + 2e]5 $

$Step 5 : 2IO^{3-} + 10I^- + 12H^+ \rightarrow 6I_2 + 6H_2O $

$IO^{3-} + 5I^- + 6H^+ \rightarrow 3I_2 + 3H_2O $

On comparing, a = 5, b = 6, c = 3, d = 3



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