Redox Reactions And Electrochemistry Ques 487
Question: $ SnCl_2 $ gives a precipitate with a solution of $ HgCl_2. $ In this process $ HgCl_2 $ is [CPMT 1983]
Options:
A) Reduced
B) Oxidised
C) Converted into a complex compound containing both $ Sn $ and $ Hg $
D) Converted into a chloro complex of $ Hg $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \overset{+2}{\mathop{SnCl_2}},+\overset{+1}{\mathop{2HgCl_2}},\to \overset{+4}{\mathop{SnCl_4}},+Hg_2Cl_2(s) $ In this reaction $ HgCl_2 $ is reduced in $ Hg $ .
