Redox Reactions And Electrochemistry Ques 419
Question: The oxidation states of the most electronegative element in the products of the reaction of $ BaO_2 $ with dilute $ H_2SO_4 $ are [IIT 1991; CBSE PMT 1992; BHU 2000]
Options:
A) 0 and - 1
B) - 1 and - 2
C) - 2 and 0
D) - 2 and + 1
Show Answer
Answer:
Correct Answer: B
Solution:
In $ H_2O_2 $ oxygen shows = - 1 (peroxide) oxidation state and in $ BaSO_4 $ oxygen shows = - 2 oxidation state.