Redox Reactions And Electrochemistry Ques 419

Question: The oxidation states of the most electronegative element in the products of the reaction of $ BaO_2 $ with dilute $ H_2SO_4 $ are [IIT 1991; CBSE PMT 1992; BHU 2000]

Options:

A) 0 and - 1

B) - 1 and - 2

C) - 2 and 0

D) - 2 and + 1

Show Answer

Answer:

Correct Answer: B

Solution:

In $ H_2O_2 $ oxygen shows = - 1 (peroxide) oxidation state and in $ BaSO_4 $ oxygen shows = - 2 oxidation state.



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